Bieber wins AL Cy Young with unanimous vote

CINCINNATI, OH - AUGUST 4: Shane Bieber #57 of the Cleveland Indians pitches in the first inning against the Cincinnati Reds at Great American Ball Park on August 4, 2020 in Cincinnati, Ohio.
Jamie Sabau / Getty Images Sport / Getty

Cleveland Indians ace Shane Bieber won the American League Cy Young Award on Wednesday and became the first pitcher since Clayton Kershaw in 2014 to win in unanimous fashion, the Baseball Writers' Association of America announced.

Minnesota Twins right-hander Kenta Maeda finished second in the voting and Toronto Blue Jays left-hander Hyun-Jin Ryu placed third.

Player Team 1st 2nd 3rd Points
Shane Bieber Indians 30 0 0 210
Kenta Maeda Twins 0 18 4 92
Hyun-Jin Ryu Blue Jays 0 4 7 51
Gerrit Cole Yankees 0 2 6 50
Dallas Keuchel White Sox 0 5 4 46

Maeda and Ryu were teammates with the Los Angeles Dodgers in 2019 and finished as Cy Young finalists after joining new teams prior to the 2020 campaign. L.A. traded the former to the Twins, while the latter joined the Blue Jays in free agency.

Bieber, meanwhile, is the fifth pitcher to win the award in Indians franchise history.

The 25-year-old righty won the Triple Crown of pitching after leading the AL in wins, ERA, and strikeouts. He also led the majors in FIP (2.07), K/9 (14.2), and ERA (1.63) while accruing the highest fWAR (3.2) among hurlers.

Bieber said he told National League Cy Young winner Trevor Bauer they should take both awards after the latter texted Bieber before the season to show him they had the same odds to win, according to Zack Meisel of The Athletic.

The two pitchers were teammates with the Indians in 2018 and 2019.

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