ACAPULCO, México (AP) — Alex De Minaur beat Casper Rudd 6-4, 6-4 on Saturday to become the first player to win back-to back titles in the Mexican Open since 2012.
The third-seeded De Minaur won his eighth ATP title to become the fourth player to repeat as champion in Mexico, the first since David Ferrer in 2010-12.
The 25-year-old Australian won his 10 consecutive match in Acapulco to break a four-match losing streaks in ATP finals, including Rotterdam earlier this year.
The sixth-seeded Ruud missed the chance to win his 11th title in the ATP and his first ATP 500 title.
De Minaur took an early break to take a 3-1 lead in the first set and both hold their serve for the 6-4 score in the first one.
In the second, both players exchanged breaks in the first four games and the Australian got a break in the seventh game to take the lead.
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AP tennis: https://apnews.com/hub/tennis
