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Giants sign Crawford to 6-year deal reportedly worth $75M

Denis Poroy / Getty Images Sport / Getty

The San Francisco Giants rewarded Brandon Crawford for his breakout 2015 campaign, agreeing to a six-year deal with the All-Star shortstop worth a reported $75 million.

''I don't think there's anywhere else I'd rather play,'' Crawford said. ''That was probably one of the biggest parts of the contract for me to know I'm going to be with the Giants for the next six years. ... To have that sense of security that I'm going to be here and my family's going to be here in the Bay Area was a huge part of that contract.''

The extension, announced by the club Tuesday, buys out Crawford's final two years of arbitration and first four seasons of free agency. Crawford's deal includes a full no-trade clause, according to Ken Rosenthal of FOX Sports.

At an average annual value of $12.5 million, Crawford's new contract represents a significant raise from the $3.175 million he earned in 2015. The extension includes a $1.2-million signing bonus.

Year Salary
2016 $5.8M
2017 $8M
2018 $15M
2019 $15M
2020 $15M
2021 $15M

The 28-year-old hit a career-high 21 homers and posted a .782 OPS across 143 games last season, securing a Silver Slugger Award as the top offensive shortstop in the National League.

A reliable glove in the middle of the infield, Crawford's range at the position also landed him a Gold Glove after saving the second-most runs in the league, according to FanGraphs.

YEAR GP 2B HR OPS WAR
2011 66 5 3 .584 0.4
2012 143 26 4 .653 2.0
2013 149 24 9 .674 2.3
2014 153 20 10 .713 3.1
2015 143 33 21 .782 4.7

Crawford, who grew up in the Bay Area rooting for the Giants, has played at least 143 games in each of his last four seasons after making his major league debut in late May 2011. He also played a key role in the Giants' 2012 and 2014 World Series titles.

- With files from The Associated Press

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